This table shows how all of the irreducible representations in the point group Oh transform upon going to lower symmetry. For example, the irreducible represenation T2g in Oh, becomes A1+ B1+ B2 in C2v. This is used to predict how decreasing the symmetry of a molecule or ion causes its electronic states to split. For the d9 Cu2+ ion the excited state is 2T2g in Oh, but when this ion undergoes a Jahn-Teller distortion to D4h symmetry (axial elongation) the 2T2g state splits into 2B2g and 2Eg states. Note that group theory only tells us that the 2T2g must split, but doesn't tell us which of the new states is lowest in energy; we need ligand field or crystal field theory for that. Also note that lowering the symmetry did not affect the spin. Click here to obtain this file in PDF format (suitable for printing).
| Oh | O | Td | D4h | D2d | C4v | C2v | D3d | D3 | C2h |
| A1g | A1 | A1 | A1g | A1 | A1 | A1 | A1g | A1 | Ag |
| A2g | A2 | A2 | B1g | B1 | B1 | A2 | A2g | A2 | Bg |
| Eg | E | E | A1g+ B1g | A1+ B1 | A1+ B1 | A1+ A2 | Eg | E | Ag+ Bg |
| T1g | T1 | T1 | A2g+ Eg | A2+ E | A2+ E | A2+ B1+ B2 | A2g+ Eg | A2+ E | Ag+ 2Bg |
| T2g | T2 | T2 | B2g+ Eg | B2+ E | B2+ E | A1+ B1+ B2 | A1g+ Eg | A1+ E | 2Ag+ Bg |
| A1u | A1 | A1 | A1u | B1 | A2 | A2 | A1u | A1 | Au |
| A2u | A2 | A2 | B1u | A1 | B2 | A1 | A2u | A2 | Bu |
| Eu | E | E | A1u+ B1u | A1+ B1 | A2+ B2 | A1+ A2 | Eu | E | Au+ Bu |
| T1u | T1 | T1 | A2u+ Eu | B2+ E | A1+ E | A1+ B1+ B2 | A2u+ Eu | A2+ E | Au+ 2Bu |
| T2u | T2 | T2 | B2u+ Eu | A2+ E | B1+ E | A2+ B1+ B2 | A1u+ Eu | A1+ E | 2Au+ Bu |