|
The inverse function to the derivative is the intergral. Instead
of finding the slope, the integral finds the area under a function.
The idea behind it is similar to the derivative, using infinitely small
parts to find a solution. Suppose we wanted to find the area under this
curve:
 One idea is to
break it into a bunch of small rectangles. We know the formula to
calculate an area of a rectangle, so we can add up all the areas to get an
approximate area for the total area of the function. As you'll
notice, rectangles don't fit functions very well, but it's a step in the
right direction!
 The formula to
add up the areas of 10 rectangles is below. Note that the formula
actually adds up rectangles placed in a different fashion (rather than the
middles intersecting with the curve, the right sides of each rectangle
intersects with the curve, this difference matters, but not for
explanation purposes).

 Not too bad,
but as we learned in Differential Calculus, smaller parts are always
better! Instead of using 10 rectangles, let's try using 100!
 Notice that
the error is a lot smaller when we use 100 rectangles than when we use
just 10. In fact, it looks almost like a perfect match! The
formula to add up all the rectangles is below.

 Note that our
answer is now much more accurate. To be perfectly accurate, an
infinite number of infinitely small rectangles must be used. This is
described using the integral. Taking the integral of f(x) yields F(x).
The integral is the curvy s shape.
 When
evaluating this integral, the final answer of the area is exactly:
 That was
pretty easy. Now say we wanted to calculate the area under between
these two curves (one is the sin(x) and the other is f(x)=x^2 - 4.
They are pictured below:
 First we need
to find where the two graphs intersect. This is accomplished by
setting the two graphs equal to each other and solving for the
x-coordinates.
 Now that we
know their intersection points, we can draw the two curves with rectangles
overlaying them.
 Once again, we
want to use infinitely small rectangles. This is accomplished by
taking the limit on the number of rectangles at infinity.
 We can
describe this situation by taking the area under the sin(x) curve
subtracted from the area under the 4-x^2 curve. In integral form,
looks something like this:

 Integrals can
be said to add dimensions to graphs. The formulas created by an
n-dimensional integral is n+1 dimensions. Likewise, derivatives take
an n-dimensional formula and make an n-1 dimensional formula. That's
why the derivative of 2-dimensional n^2 is a 1-dimensional 2n, and the
integral of 2-dimensional n^2 is a 3-dimensional graph, n^3/3. An
application of integrals beyond finding areas under curves, is finding
volumes of functions rotated around an axis. For example, imagine
the following graph is rotated around the x-axis, making a 3-dimensional
object. What is the volume of this object?

 First, we know
that the area of a circle is:
 Instead of
integrating an infinite number of thin lines to make an area, we are going
to integrate an infinite number of thin circles to find a volume.
Instead of having a constant r value, we want a variable.
This radius is the height of our function, or just plane variable f.
 When we
substitute in cos(x) for f, we have:
 This integral
evaluates to:

 So the
function f = cos(x) when revolved around the x-axis and integrated from 0
to 1, has a total volume of about 2.285 cubic units. This is
called the disc (or disk) method. Integral Calculus is another vast
field of research. I highly recommend the first reference link
below, as it has an extensive library of information regarding integrals.
To evaluate any integral try using the Integrator. |